7+21t-16t^2=0

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Solution for 7+21t-16t^2=0 equation:



7+21t-16t^2=0
a = -16; b = 21; c = +7;
Δ = b2-4ac
Δ = 212-4·(-16)·7
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{889}}{2*-16}=\frac{-21-\sqrt{889}}{-32} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{889}}{2*-16}=\frac{-21+\sqrt{889}}{-32} $

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